If a committee of six students is chosen at random from a group of six boys and four girls, what is the probability that the committee contains the same number of boys and girls? Express your answer as a common fraction.

mathisopandcool May 19, 2021

#1**+2 **

Number of ways for the committee to have 3 boys, 3 girls: \(\binom{6}{3} \cdot \binom{4}{3} = 20 \cdot 4 = 80.\)

Number of total ways: \(\binom{10}{6} = 210\)

So, the answer is \(\frac{8}{21}.\)

ilovepizza547 May 19, 2021