If A is one greater than B, what is A^2 - B^2, in terms of A and B?
GIVEN : A = B+1
Then
A^2 - B^2 = (B+1)^2 - B^2 = B^2 +2B +1 - B^2 = 2B+1
A^2 - B^2 = 2B+1
Not sure if I understand your question:
But, if (A + 1) = B, then:
Solve for A:
(A + 1)^2 - B^2 = 0
The left hand side factors into a product with two terms:
(1 + A - B) (1 + A + B) = 0
Split into two equations:
1 + A - B = 0 or 1 + A + B = 0
Subtract 1 - B from both sides:
A = B - 1 or 1 + A + B = 0
Subtract B + 1 from both sides:
A = B - 1 or A = -B - 1 OR: B=+or-(A + 1)
CPhill: Please check this out. Thanks.
GIVEN : A = B+1
Then
A^2 - B^2 = (B+1)^2 - B^2 = B^2 +2B +1 - B^2 = 2B+1
A^2 - B^2 = 2B+1
A = B+1 then A-1 = B
Then A^2 - B^2 = A^2 - (A-1)^2
= A^2 - (A^2 -2A +1)
= A^2 - A^2 + 2A -1 = 2A-1