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If all the dimensions of a rectangular solid are increased by 2 times, what is the change in the volume of the shape?

Guest Dec 14, 2014

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 #2
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If the dimensions of a solid double    That is they (the lengths) are 2 times  greater

then the surface area will increase by a factor of 2^2=4   That is it will be 4 times  greater

and

the volume will increase by a factor of 2^3 =8.    That is it will be  8 times greater.

 

This is a really handy thing to know 

Melody  Dec 14, 2014
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 #1
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what is 4*(10-3-2+4+1)*2 square-routed?

Guest Dec 14, 2014
 #2
avatar+92206 
+10
Best Answer

If the dimensions of a solid double    That is they (the lengths) are 2 times  greater

then the surface area will increase by a factor of 2^2=4   That is it will be 4 times  greater

and

the volume will increase by a factor of 2^3 =8.    That is it will be  8 times greater.

 

This is a really handy thing to know 

Melody  Dec 14, 2014
 #3
avatar+92206 
+5

I am just thinking here.

If we increase something by a factor of 1 this is meaningless.  To a mathematician it means multiply by 1 so it stays the same and is not increased at all.

 

If you told a lay person in the street to increase the size of something by a factor of 1 they could either mistakenly add one unit to it or erroneously double the size. They could easily think that if it was 4 units long before and increase it by a factor of 1 that it must now be 8 units (what it was before plus one more of what it was before 1+1more) .  Of course this is really increasing by a factor of 2 (1*2) but I can see how it could be very confusing.

Melody  Dec 14, 2014

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