If angle A+angle B +angle C = $${\mathtt{\pi}}$$ (180 degrees) ,$${\mathtt{\pi}}$$-A=B+C

then sinA=sin($${\mathtt{\pi}}$$-A)=sin(B+C)

but A might not equal to B+C, right?

Guest Feb 4, 2015

#2**+5 **

Mmm

$$\\\pi-A=B+C\;\rightarrow\;A=\pi-(B+C)\\

or\\

A=B+C$$

But I can add 2pi*n to these answers where n is an integer

$$\\A=\pi-(B+C)+2n\pi=(2n+1)\pi-(B+C)\\

or\\

A=B+C +2n\pi$$

Mmm

$$\\A=(2n+1)\pi-(B+C)\\

or\\

A=2n\pi+(B+C)\\\\\\\\

$I think the general formula for this would be$\\

A=(-1)^n(B+C)+n\pi$$

** **

**I think that is right but I really need another mathematician to check my working. :))**

Melody
Feb 4, 2015

#1**+3 **

A+B+C = Pi

B + C = Pi - A

cos(B +C)= cos (Pi -A)

cos (B+C) = -(cos A)

-(cos A) = cos(-A)

so that,

cos(B +C) = cos(-A)

now we cut cos

B+C = -A//

Sasini
Feb 4, 2015

#2**+5 **

Best Answer

Mmm

$$\\\pi-A=B+C\;\rightarrow\;A=\pi-(B+C)\\

or\\

A=B+C$$

But I can add 2pi*n to these answers where n is an integer

$$\\A=\pi-(B+C)+2n\pi=(2n+1)\pi-(B+C)\\

or\\

A=B+C +2n\pi$$

Mmm

$$\\A=(2n+1)\pi-(B+C)\\

or\\

A=2n\pi+(B+C)\\\\\\\\

$I think the general formula for this would be$\\

A=(-1)^n(B+C)+n\pi$$

** **

**I think that is right but I really need another mathematician to check my working. :))**

Melody
Feb 4, 2015