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If angle A+angle B +angle C = π (180 degrees) ,π-A=B+C

then sinA=sin(π-A)=sin(B+C)

but A might not equal to B+C, right?

 Feb 4, 2015

Best Answer 

 #2
avatar+118703 
+5

Mmm

πA=B+CA=π(B+C)orA=B+C

 

But I can add 2pi*n to these answers where n is an integer

 

A=π(B+C)+2nπ=(2n+1)π(B+C)orA=B+C+2nπ

 

Mmm

A=(2n+1)π(B+C)orA=2nπ+(B+C)$Ithinkthegeneralformulaforthiswouldbe$A=(1)n(B+C)+nπ

 

I think that is right but I really need another mathematician to check my working.  :))

 Feb 4, 2015
 #1
avatar+752 
+3

A+B+C = Pi

B + C    =  Pi - A

cos(B +C)= cos (Pi -A)

cos (B+C) = -(cos A)

-(cos A) = cos(-A)

so that,

cos(B +C)   = cos(-A)

now we cut cos

B+C    = -A//

 Feb 4, 2015
 #2
avatar+118703 
+5
Best Answer

Mmm

πA=B+CA=π(B+C)orA=B+C

 

But I can add 2pi*n to these answers where n is an integer

 

A=π(B+C)+2nπ=(2n+1)π(B+C)orA=B+C+2nπ

 

Mmm

A=(2n+1)π(B+C)orA=2nπ+(B+C)$Ithinkthegeneralformulaforthiswouldbe$A=(1)n(B+C)+nπ

 

I think that is right but I really need another mathematician to check my working.  :))

Melody Feb 4, 2015

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