+0  
 
0
526
1
avatar

If BC is twice as long as AB, which equations would let you find the length of AC?

Guest May 28, 2014

Best Answer 

 #1
avatar+93911 
+5

Is some of this question missing?

I am going to use the cosine rule.

$$\begin{array}{rll}
\overline{AC}^2&=&(2x)^2+x^2-(2*2x*x*Cos( \overline{AC}^2&=&4x^2+x^2-(4x^2Cos( \overline{AC}^2&=&5x^2-(4x^2Cos( \overline{AC}^2&=&x^2(5-4Cos( \overline{AC}&=&x\sqrt{5-4Cos( \overline{AC}&=&\overline{AB}\sqrt{5-4Cos( \end{array}$$

That should be okay if i didn't make any stupid mistakes.

Melody  May 29, 2014
 #1
avatar+93911 
+5
Best Answer

Is some of this question missing?

I am going to use the cosine rule.

$$\begin{array}{rll}
\overline{AC}^2&=&(2x)^2+x^2-(2*2x*x*Cos( \overline{AC}^2&=&4x^2+x^2-(4x^2Cos( \overline{AC}^2&=&5x^2-(4x^2Cos( \overline{AC}^2&=&x^2(5-4Cos( \overline{AC}&=&x\sqrt{5-4Cos( \overline{AC}&=&\overline{AB}\sqrt{5-4Cos( \end{array}$$

That should be okay if i didn't make any stupid mistakes.

Melody  May 29, 2014

24 Online Users

avatar
avatar

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.