+0  
 
+1
278
7
avatar

if city A's population is 5000 with a yearly growth rate of 4% and city B has a population of 8000 with a yearly growth rate of 2% when will city A surpass city B?

Guest May 2, 2017
 #1
avatar+39 
0

Hold up

ReChan  May 2, 2017
 #2
avatar+39 
0

So equation goes like

5000x+.04

8000x+.02

sub x with 1,2,3,etc

keep going till a passes

ReChan  May 2, 2017
 #3
avatar
0

But what is the answer.

And what is the value of A and B.

Guest May 2, 2017
 #4
avatar+39 
0

I ain't taking away yo education XD Figure it put urself took me long enough to find out

ReChan  May 2, 2017
 #5
avatar
0

I'm doing Java code and I need the answer to know if my code is working and I don't know the answer so I don't know if my code is giving me the right answer.

Guest May 2, 2017
 #6
avatar+39 
+1

Sorry dude got my own stuff to worry bout. Just use a calculator if ur lazy

ReChan  May 2, 2017
 #7
avatar+89709 
+2

 

We want to solve this

 

5000 (1.04)^t   =  8000 (1.02)^t       rearrange as

 

(1.04)^t  / (1/02)^t   =   8000/ 5000

 

(1.04 / 1/02)^t   =  8/5

 

(52/51)^t  =  8/5            take the log of both sides

 

log (52/51)^t   =  log (8/5)     and we can write

 

 t * log (52/51)  =  log (8/5)        divide both sides by log (52/51)

 

t =   log (8/5)  / log (52/51)  =   after  ≈ 24.2 years

 

 

cool cool cool

CPhill  May 2, 2017

27 Online Users

avatar
avatar
avatar

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.