+0  
 
0
300
4
avatar+1898 

If each resistor in the circuit shown is 5.0 Ω, and the battery is 12.0 V, what does the second ammeter (A2) read?

 

 

   

0.24 A

0.96 A

0.12 A

0.48 A

 Apr 21, 2020
 #1
avatar+25994 
+2

R2 and R3  are in parallel....their effective resistance is    (r2 * r3)/ (r2+r3) = 25/10 = 2.5 ohms

  (they each have the same current through them)

 

the resistance of the entire circuit is   R4 + 2.5 ohms + R1 = 12.5 ohms

 

The current in the circuit        V/R = I        12 v/ 12.5 ohms = 960 mA

 

R2 and R3 split this current    960/2 = 480 mA   (or  .48 A )

 Apr 22, 2020
 #2
avatar+1898 
0

i forgot to include what i thought it was! but i did it correctly. thank you. if you may help me with a few more questions.

jjennylove  Apr 22, 2020
 #3
avatar+25994 
+1

Sure!  Just hangin' at the house makin' beer......

ElectricPavlov  Apr 22, 2020
 #4
avatar+1898 
0

Oh fun! (:

jjennylove  Apr 22, 2020

7 Online Users

avatar