If each resistor in the circuit shown is 5.0 Ω, and the battery is 12.0 V, what does the second ammeter (A2) read?

0.24 A

0.96 A

0.12 A

0.48 A

jjennylove Apr 21, 2020

#1**+2 **

R2 and R3 are in parallel....their effective resistance is (r2 * r3)/ (r2+r3) = 25/10 = 2.5 ohms

(they each have the same current through them)

the resistance of the entire circuit is R4 + 2.5 ohms + R1 = 12.5 ohms

The current in the circuit V/R = I 12 v/ 12.5 ohms = 960 mA

R2 and R3 split this current 960/2 = 480 mA (or .48 A )

ElectricPavlov Apr 22, 2020

#2**0 **

i forgot to include what i thought it was! but i did it correctly. thank you. if you may help me with a few more questions.

jjennylove
Apr 22, 2020