If each resistor in the circuit shown is 5.0 Ω and the battery is 12.0 V, what does the second voltmeter (V2) read?
0.35 V
0.96 V
2.4 V
4.8 V
4.8 i think ?
We already determined the current through the circuit (in a previous question)
I R4 = Voltage R4 = 5 ohms and current was from previous Q
For this circuit, what will be the voltage drop across R3 ?
21.3 V
14.2 V
45.0 V
9.47 V
i meant this one
NO.......
Current in the circuit v/r = i
45/(20+30+45) = 473 mA
Votage across R3 = IR = .473 * 45 = 21.3 v
ALL of the voltage will be dropped around the circuit .....45 v will be dropped
R3 portion will be a fraction 45 / (20+30+45) x 45 v = 21.3 v
im so sorry, i dont know why i cant seem to understand these! it makes sense what you have wrote, i jsut hope i can apply to the others! thank you