If each resistor in the circuit shown is 5.0 Ω and the battery is 12.0 V, what does the second voltmeter (V2) read?
4.8 i think ?
We already determined the current through the circuit (in a previous question)
I R4 = Voltage R4 = 5 ohms and current was from previous Q
Current in the circuit v/r = i
45/(20+30+45) = 473 mA
Votage across R3 = IR = .473 * 45 = 21.3 v
ALL of the voltage will be dropped around the circuit .....45 v will be dropped
R3 portion will be a fraction 45 / (20+30+45) x 45 v = 21.3 v