If each resistor in the circuit shown is 5.0 Ω and the battery is 12.0 V, what does the second voltmeter (V2) read?
0.35 V
0.96 V
2.4 V
4.8 V
pretty sure its 4.8 V
Total resistance = 5 + 5 + 5*5/(10) = 12.5 ohms
Current through the circuit = 12 v / 12.5 ohms = .96 A
V2 = I R2 = .96 A * 5 ohms = 4.8 v across R4