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what is the probability that I will end up with one card from each suit?

 Dec 3, 2020
 #1
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The probability is 64/1225.

 Dec 3, 2020
 #2
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The first card is a given

 

On the second draw, we have  a (39/52)  = (3/4)  probability of drawing a different suite from the first draw

 

On the third draw we have  a (26/52) = (1/2) probability of drawing a suite different from the first two draws

 

On the last draw we  have a (13/52) = (1/4) probability of drawing a different suite from the ones we  drew on the first three draws

 

So  the probability =    ( 3/4) ( 1/2) ( 1/4)  =   3 /32

 

 

cool cool cool

 Dec 3, 2020
edited by CPhill  Dec 3, 2020

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