what is the probability that I will end up with one card from each suit?
The first card is a given
On the second draw, we have a (39/52) = (3/4) probability of drawing a different suite from the first draw
On the third draw we have a (26/52) = (1/2) probability of drawing a suite different from the first two draws
On the last draw we have a (13/52) = (1/4) probability of drawing a different suite from the ones we drew on the first three draws
So the probability = ( 3/4) ( 1/2) ( 1/4) = 3 /32