If ​n(A×​B)=75 and ​n(A) =15, find​ n(B).

Well, um...I don't know if I fully understand this topic, but I'll try to answer  .

n(A x B) when distributed would be n(A)* n(B).

And n(A x B) is 75.

We also know n(A) = 15.

So if n(A)* n(B) is equivalent to n(A x B), then n(A)* n(B) = 75.

N(A) is 15, so substitute 15 for n(A) to get 15* n(B) = 75.

Divide both sides by 15 and get n(B) = 5.

So n(B) = 5.

Correct me if I'm wrong.