If t is a real number, what is the maximum possible value of the expression -t^2 + 18t - 4?
If t is a real number, what is the maximum possible value
of the expression - t^2 + 18t - 4 ?
Hello Guest!
\(f(t)= -t^2 + 18t - 4\\ \frac{df(t)}{dt}=-2t+18=0\\ -2t=-18\)
\(t=9\)
\(f(t)= -t^2 + 18t - 4=-9^2+18\cdot 9-4\\ \color{blue}f(t)_{max}=77\)
\(The\ maximum\ possible\ value\)
\(of\ the\ Expression\ {\color{BrickRed}[ -t^2 + 18t - 4]}\ \color{blue} is\ 77.\)
Thanks anonymus!
!
Without calculus:
this is a dome shaped parabola (due to the -1 coefficient of t2)
maximum value will occur at the vertex t value of - b/2a = - 18 / (2*-1) = t=9
this is th maximum t
since this is a function of 't' you will need to sub in this value of t into the equation to calulate the maximum value of the function
-9^2 + 18(9) - 4 = 77