+0

# If , then

0
800
2

If , then

Guest Aug 5, 2014

#2
+92254
+10

$$\frac{4}{3}x-\frac{1}{2}=0$$

I would do this question by multiplying both sides by the lowest common denominator which is 6.

That way you get rid of all the fractions right from the begining.

$$\begin{array}{rll} 6\times \left(\frac{4}{3}x-\frac{1}{2}\right)&=&0 \times 6\\\\ \frac{6\times 4}{3}x-\frac{6}{2}&=&0\\\\ 8x-3&=&0\\\\ 8x&=&3\\\\ x&=&\frac{3}{8}\\\\ \end{array}$$

Melody  Aug 5, 2014
Sort:

#1
+3450
+10

Here, we just need to get x alone, or in other words, x = something.

$$\begin{array}{l} \frac{4}{3}x-\frac{1}{2}=0\qquad\mbox{Add \frac{1}{2} to both sides}\\ \frac{4}{3}x=\frac{1}{2}\qquad\mbox{Divide both sides by \frac{4}{3}}\\ x=\frac{1}{2}\div\frac{4}{3}\qquad\mbox{Remember, when diving two fractions, multiply by the reciprocal (flip-flop the second fraction)}\\ x=\frac{1}{2}\times\frac{3}{4}\qquad\mbox{Multiply the left side out}\\ x=\frac{3}{8} \end{array}$$

To check this, put in $$\frac{3}{8}$$ for x!

$$\begin{array}{l} \frac{4}{3}x-\frac{1}{2}=0\\ \frac{4}{3}\times\frac{3}{8}-\frac{1}{2}=0\\ \frac{12}{24}-\frac{1}{2}=0\qquad\mbox{Reduce the first fraction}\\ \frac{1}{2}-\frac{1}{2}=0\\ 0=0 \end{array}$$

It works, because 0 does equal 0!

#2
+92254
+10

$$\frac{4}{3}x-\frac{1}{2}=0$$

I would do this question by multiplying both sides by the lowest common denominator which is 6.

That way you get rid of all the fractions right from the begining.

$$\begin{array}{rll} 6\times \left(\frac{4}{3}x-\frac{1}{2}\right)&=&0 \times 6\\\\ \frac{6\times 4}{3}x-\frac{6}{2}&=&0\\\\ 8x-3&=&0\\\\ 8x&=&3\\\\ x&=&\frac{3}{8}\\\\ \end{array}$$

Melody  Aug 5, 2014

### 31 Online Users

We use cookies to personalise content and ads, to provide social media features and to analyse our traffic. We also share information about your use of our site with our social media, advertising and analytics partners.  See details