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If there are 800000 tickets, and I use 2000 tickets, what is the % of me winning?

 Jul 9, 2015
 #2
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If there is only ONE winning ticket, when you buy 1 ticket you have a 1/800000 chance of winning.  Buy another ticket from the 79999 tickets remaining and you have a 1/79999 chance of winning....etc

So    1/800000 + 1/799999 + 1/799998 ..........1/798001   =   

0.0025031286517031437518075585925891297125507127954989...         I think!    Can anyone 2nd that?
 Jul 9, 2015
 #3
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=

0.0025031286517031437518075585925891297125507127954989...     
.
 Jul 9, 2015
 #4
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  Sorry,   as 'Anonymous' poster it wouldn't let me post by 'pasting' the answer, but here it is

= .002503128651703143....
 Jul 9, 2015
 #5
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x 100 = .2503 %

 Jul 9, 2015
 #6
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If there is one winning ticket then you have 2000 chances to win out of a possible 800000 tickets.

 

$${\frac{{\mathtt{2\,000}}}{{\mathtt{800\,000}}}}{\mathtt{\,\times\,}}{\mathtt{100}} = {\frac{{\mathtt{1}}}{{\mathtt{4}}}} = {\mathtt{0.25}}$$  

 

That is 0.25% chance     (exactly 1 chance in 400)

 Jul 10, 2015

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