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avatar+281 

If we use (x+) to indicate the following sum
   1 + 2 + 3 + ... + x
then find the value of k in the following equation
(28+) - (27+) = (k+)

kes1968  Aug 12, 2015

Best Answer 

 #4
avatar+78750 
+10

The sum of the first "k" positive integers is given by :   (k)(k + 1)/2

 

So  (x +)   where x =  28  is just  (28)(29) /2     and  (x+) where x = 27  is just (27)(28)/2 

 

So we have

 

(28)(29)/2 -  (270(28)/2        ..... factor out 28/2

 

[28/2] [ 29 - 27]=

 

[14] [2]  = 28

 

And notice that :

 

1 + 2 + 3 + 4 + 5 + 6 + 7  = 28   

 

So this equals the sum of the first seven positive integers  =  (7)(8)/2  = 56/2 = (7+)

 

 

 

  

CPhill  Aug 12, 2015
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4+0 Answers

 #1
avatar+78750 
+5

(28+) - (27+) =

 

(28)(29)/ 2 - (27)(28)/2  =

 

(28) [ (29) - (27) ] / 2 =

 

(28/2) (2) = 28  =  (7)(8)/ 2 =   (7+)   ...so k = 7

 

 

  

CPhill  Aug 12, 2015
 #2
avatar+281 
0

I AN NOT GETTING WHAT YOU HAVE GIVEN PLEASE EXPLAIN YOUR ANS TO ME MORE BRIEFLY

kes1968  Aug 12, 2015
 #3
avatar+18715 
+10

If we use (x+) to indicate the following sum
   1 + 2 + 3 + ... + x
then find the value of k in the following equation
(28+) - (27+) = (k+)

 

$$\small{\text{$
\begin{array}{rcl}
(28+)-(27+) = (k+) = 28 &=& S_k \qquad (28+) = S_{28} \quad (27+)=S_{27}\\\\
S_{28}-S_{27} = t_{28} = 28&=&S_k\\\\
S_k &=& t_1 \cdot \dbinom{k}{1} + d\cdot \dbinom{k}{2} \qquad t_1=d=1\\\\
S_k &=& \dbinom{k}{1} + \dbinom{k}{2} = \dbinom{k+1}{2} = 28\\\\ \\
\dfrac{k(k+1)}{2} &=& 28 \\\\
k(k+1) &=& 56\\\\
k^2+k-56&=&0\\\\
\Rightarrow k &=& \dfrac{-1+15}{2} = 7\\\\
\mathbf{S_k = (k+) }& \mathbf{=} & \mathbf{(7+)}\\\\
(7+)=1+2+3+4+5+6+7&=&28 \\
\end{array}
$}}$$

 

heureka  Aug 12, 2015
 #4
avatar+78750 
+10
Best Answer

The sum of the first "k" positive integers is given by :   (k)(k + 1)/2

 

So  (x +)   where x =  28  is just  (28)(29) /2     and  (x+) where x = 27  is just (27)(28)/2 

 

So we have

 

(28)(29)/2 -  (270(28)/2        ..... factor out 28/2

 

[28/2] [ 29 - 27]=

 

[14] [2]  = 28

 

And notice that :

 

1 + 2 + 3 + 4 + 5 + 6 + 7  = 28   

 

So this equals the sum of the first seven positive integers  =  (7)(8)/2  = 56/2 = (7+)

 

 

 

  

CPhill  Aug 12, 2015

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