If \(n=1d41_8\), where \(d\) represents a base-8 digit (and \(1d41_8\) represents a four-digit number whose second digit is \(d\)), then what is the sum of all possible values of \(n\) in base 10?
\(n= 1+4*8 + d*8^2 + 1*8^3 \) (base 10) where d is and integer and \(0\le d \le7\)
n= 1 + 32 +68d + 512
you can take it from there.
