if width or a rectangle is 2 less then the langth, what is the langth, width, and area with a perimiditer of 52?

Guest Mar 7, 2017

#1**+5 **

W = L - 2

Perimeter = 2 ( W + L) = 52 ....so.......

52 = 2 ( L - 2 + L) simplify

52 = 2 ( 2L - 2) divide both sides by 2

26 = 2L - 2 add 2 to both sides

28 = 2L divide both sides by 2

14 = L .... so W = L - 2 = 14 - 2 = 12

Area = L x W = 14 x 12 = 168 sq units

CPhill
Mar 7, 2017

#2**+5 **

Best Answer

Thank you so much CPill! could you also do it with 68(perimiter) and 288(area)

Guest Mar 7, 2017