if width or a rectangle is 2 less then the langth, what is the langth, width, and area with a perimiditer of 52?
W = L - 2
Perimeter = 2 ( W + L) = 52 ....so.......
52 = 2 ( L - 2 + L) simplify
52 = 2 ( 2L - 2) divide both sides by 2
26 = 2L - 2 add 2 to both sides
28 = 2L divide both sides by 2
14 = L .... so W = L - 2 = 14 - 2 = 12
Area = L x W = 14 x 12 = 168 sq units
Thank you so much CPill! could you also do it with 68(perimiter) and 288(area)