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if width or a rectangle is 2 less then the langth, what is the langth, width, and area with a perimiditer of 52?

Guest Mar 7, 2017

Best Answer 

 #2
avatar
+5

Thank you so much CPill! could you also do it with 68(perimiter) and 288(area)

Guest Mar 7, 2017
 #1
avatar+86859 
+5

W = L - 2

 

Perimeter = 2 ( W + L)  = 52   ....so.......

 

52  =  2 ( L - 2 + L)    simplify

 

52 = 2 ( 2L - 2)    divide both sides by 2

 

26  = 2L - 2      add 2 to both sides

 

28  = 2L        divide both sides by 2

 

14 = L     ....   so W  = L - 2   =   14 -  2   = 12

 

 

Area  = L x W    =   14 x 12   =  168 sq units

 

 

cool cool cool

CPhill  Mar 7, 2017
 #2
avatar
+5
Best Answer

Thank you so much CPill! could you also do it with 68(perimiter) and 288(area)

Guest Mar 7, 2017
 #3
avatar+86859 
+5

W = L - 2

 

Perimeter = 2 ( W + L)  = 68   ....so.......

 

68  =  2 ( L - 2 + L)    simplify

 

68 = 2 ( 2L - 2)    divide both sides by 2

 

34  = 2L - 2      add 2 to both sides

 

36  = 2L        divide both sides by 2

 

18 = L     ....   so W  = L - 2   =   18 -  2   = 16

 

 

Area  = L x W    =   18 x 16   =  288 sq units

 

 

cool cool cool

CPhill  Mar 7, 2017
 #4
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0

NM, I used your equation

Guest Mar 7, 2017
 #5
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0

oh.

opps.

Guest Mar 7, 2017

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