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# if width or a rectangle is 2 less then the langth, what is the langth, width, and area with a perimiditer of 52?

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if width or a rectangle is 2 less then the langth, what is the langth, width, and area with a perimiditer of 52?

Guest Mar 7, 2017

#2
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Thank you so much CPill! could you also do it with 68(perimiter) and 288(area)

Guest Mar 7, 2017
#1
+88992
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W = L - 2

Perimeter = 2 ( W + L)  = 52   ....so.......

52  =  2 ( L - 2 + L)    simplify

52 = 2 ( 2L - 2)    divide both sides by 2

26  = 2L - 2      add 2 to both sides

28  = 2L        divide both sides by 2

14 = L     ....   so W  = L - 2   =   14 -  2   = 12

Area  = L x W    =   14 x 12   =  168 sq units

CPhill  Mar 7, 2017
#2
+5

Thank you so much CPill! could you also do it with 68(perimiter) and 288(area)

Guest Mar 7, 2017
#3
+88992
+5

W = L - 2

Perimeter = 2 ( W + L)  = 68   ....so.......

68  =  2 ( L - 2 + L)    simplify

68 = 2 ( 2L - 2)    divide both sides by 2

34  = 2L - 2      add 2 to both sides

36  = 2L        divide both sides by 2

18 = L     ....   so W  = L - 2   =   18 -  2   = 16

Area  = L x W    =   18 x 16   =  288 sq units

CPhill  Mar 7, 2017
#4
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Guest Mar 7, 2017
#5
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oh.

opps.

Guest Mar 7, 2017