+0  
 
0
59
5
avatar

if width or a rectangle is 2 less then the langth, what is the langth, width, and area with a perimiditer of 52?

Guest Mar 7, 2017

Best Answer 

 #2
avatar
+5

Thank you so much CPill! could you also do it with 68(perimiter) and 288(area)

Guest Mar 7, 2017
Sort: 

5+0 Answers

 #1
avatar+77139 
+5

W = L - 2

 

Perimeter = 2 ( W + L)  = 52   ....so.......

 

52  =  2 ( L - 2 + L)    simplify

 

52 = 2 ( 2L - 2)    divide both sides by 2

 

26  = 2L - 2      add 2 to both sides

 

28  = 2L        divide both sides by 2

 

14 = L     ....   so W  = L - 2   =   14 -  2   = 12

 

 

Area  = L x W    =   14 x 12   =  168 sq units

 

 

cool cool cool

CPhill  Mar 7, 2017
 #2
avatar
+5
Best Answer

Thank you so much CPill! could you also do it with 68(perimiter) and 288(area)

Guest Mar 7, 2017
 #3
avatar+77139 
+5

W = L - 2

 

Perimeter = 2 ( W + L)  = 68   ....so.......

 

68  =  2 ( L - 2 + L)    simplify

 

68 = 2 ( 2L - 2)    divide both sides by 2

 

34  = 2L - 2      add 2 to both sides

 

36  = 2L        divide both sides by 2

 

18 = L     ....   so W  = L - 2   =   18 -  2   = 16

 

 

Area  = L x W    =   18 x 16   =  288 sq units

 

 

cool cool cool

CPhill  Mar 7, 2017
 #4
avatar
0

NM, I used your equation

Guest Mar 7, 2017
 #5
avatar
0

oh.

opps.

Guest Mar 7, 2017

15 Online Users

avatar
avatar
avatar
We use cookies to personalise content and ads, to provide social media features and to analyse our traffic. We also share information about your use of our site with our social media, advertising and analytics partners.  See details