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If x^2 = 16. what is the sum of all possible values of x?

 Jun 23, 2020
 #1
avatar+9789 
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If x^2 = 16. what is the sum of all possible values of x?

 

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 \(x^2=16\)            | take the root

 \(x=\pm\sqrt{16}\)       | calculate the root

 \(x_1=4\\ x_2=-4\)

 \(x_1+x_2=4+(-4)=0\)

 

 \(The\ sum\ of\ all\ possible\ values\ of\ x\ is\ 0\ .\)

laugh  !

 Jun 23, 2020
 #2
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If \(x^2 = 16\), then the possible values of x are \(\pm 4\), meaning 4 and -4.

\(4+-4=0\), so the sum of all possible values of x are 0. 

 Jun 23, 2020

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