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# If x^2 = 16. what is the sum of all possible values of x?

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If x^2 = 16. what is the sum of all possible values of x?

Jun 23, 2020

#1
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If x^2 = 16. what is the sum of all possible values of x?

Hello Guest!

$$x^2=16$$            | take the root

$$x=\pm\sqrt{16}$$       | calculate the root

$$x_1=4\\ x_2=-4$$

$$x_1+x_2=4+(-4)=0$$

$$The\ sum\ of\ all\ possible\ values\ of\ x\ is\ 0\ .$$

!

Jun 23, 2020
#2
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If $$x^2 = 16$$, then the possible values of x are $$\pm 4$$, meaning 4 and -4.

$$4+-4=0$$, so the sum of all possible values of x are 0.

Jun 23, 2020