If x^2 = 16. what is the sum of all possible values of x?

If x^2 = 16. what is the sum of all possible values of x?

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 $x^2=16$            | take the root

 $x=\pm\sqrt{16}$       | calculate the root

 $x_1=4\\ x_2=-4$

 $x_1+x_2=4+(-4)=0$

 $The\ sum\ of\ all\ possible\ values\ of\ x\ is\ 0\ .$

  !

If $x^2 = 16$, then the possible values of x are $\pm 4$, meaning 4 and -4.

$4+-4=0$, so the sum of all possible values of x are 0.