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If y = x and y = -x, then what will be the graph? ( Kindly could you provide the graph? )

 Nov 26, 2017

Best Answer 

 #1
avatar+60 
+2

  Does this help?

 Nov 26, 2017
 #1
avatar+60 
+2
Best Answer

  Does this help?

Conman13 Nov 26, 2017
 #2
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+1

Could you tell me, sir, why two lines go through the middle points in the graphs? (one to the right side and the another to the left side) I am confused  

 Nov 27, 2017
 #3
avatar+118608 
+1

When y=x it means exactly that. Whatever x is y is the same so some of the points on the graph will be

(1,1)     (100,100)        (3.5,3.5)       (-2,-2)      etc etc etc

So if x=0 y=0      The point (0,0) will be on this graph.

 

 

When y=-x it means that whatever x is y is the negative of it so some of the points on the graph will be

(1,-1)     (100,-100)        (3.5,-3.5)       (-2,+2)      etc etc etc

So if x=0 y=-0 =0        The point (0,0) will be on this graph as well.

 

Does that help? 

 Nov 27, 2017
 #4
avatar+55 
+1

I understood but I have a doubt here. 

When y = x, the line goes through the middle (0,0) in the right direction in the graph, then why does the line go through the middle (0,0) in the left direction in the graph, when y = -x? I mean both lines should be in the same direction either in the right direction or in the left direction because the two equations ( y = x and y = -x ) shows same values 0,0 ( if x = 0, y = 0) and 0,0 ( if x = 0, y = -0 = 0). I am confused here. Could you explain, please?

Indranil  Nov 27, 2017
 #5
avatar+118608 
+1

Graphing is confusing especially if you are new at it. 

 

y=x

x 0 1 2 3 4 5
y 0 1        

Now graph those points on a number plane.    Conman13 has already done it for you. :)

 

 

 

y=-x     (The negative sign has to go in front of the x value to get the y yalue.

x 0 1 2 3 4 5
y -0=0 -1 -2      

Now graph those points on a number plane.

 

 

 

 

The only time that y=x=-x is when x=0  and y=0 so that i the only point of intersection for these 2 graphs.

Melody  Nov 27, 2017
 #6
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+1

Thank you all, sir.

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