#2**-1 **

Since AQ is an angle bisector, angle CAQ is 45 degrees. We are told that angle PAQ is 13 degrees, so angle RAC is 45 + 13 = 58 degrees.

Guest Jul 27, 2020

#6**0 **

Wait you wont give the person who solves this one million dollars i bet :p

Sub2JessieGamez Jul 27, 2020

#9**+1 **

Assuming that P, Q, and R are on BC (in the order B, P, Q, R, C):

Angle(BAC) = 90.

Since AQ is an angle bisector, angle(BAQ) = 45.

Since P is between B and Q and angle(PAQ) = 13, angle(BAP) = angle(BAQ) - angle(PAQ)

---> angle(BAP) = 45 - 13 = 32.

Since AP is an altitude, angle(BPA) = 90.

In triangle(BAP), angle(BAP) = 32 and angle(BPA) = 90 ---> angle(ABP) = 58.

In triangle(BAC), angle(BAC) = 90 and angle(ABP) = 58 ---> angle(ACB) = 32.

Since AR is a median of a right triangle, RA = RB = RC.

Since RA = RC, triangle(ARC) is an isosceles triangle.

Since angle(ACB) = 32, **ange(CAR) = 32**.

geno3141 Jul 28, 2020