+0  
 
0
117
4
avatar+273 

I need help asap! Thanks in advance! 

LaughingFace  Apr 25, 2018
 #1
avatar+963 
+2

87. 

 

Since there are three digits and each digit has 10 options,

 

there are a total of:

 

10^3 ways of identifying students. 

 

The first number can be a 0, since it is not supposed to be a number, just an identification. 

 

10^3 = 1000

 

That is you final answer. 

GYanggg  Apr 25, 2018
 #2
avatar+963 
+2

88.

 

There are a total of:

 

\(\binom{15}{4}\)

 

ways to choose the debaters. 

 

This is equal to 1365.

 

Since we need those four people, with only one way to choose them.

 

The chance this will happen is 1/1365. 

GYanggg  Apr 25, 2018
 #3
avatar+3270 
+1

89. The probability of choosing a dime first is \(\frac{2}{10}=\frac{1}{5}\) .

Next, picking a quarter without replacement is just \(\frac{3}{10}\).

Multiplying, we get \(\frac{1}{5}*\frac{3}{10}=\frac{3}{50}\)

tertre  Apr 25, 2018
 #4
avatar+3270 
+1

90.

The total number of marbles: \(12+8+4+16=40\)

Blue Marble: \(\frac{4}{40}=\frac{1}{10}\)

Red marble: \(\frac{12}{40}=\frac{3}{10}\)

So, the answer is just \(\frac{1}{10}*\frac{3}{10}=\boxed{\frac{3}{100}}\)

smileysmiley

tertre  Apr 25, 2018

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