If you could please help me out with this that would be awesome!

https://gyazo.com/272dff413b9d2d9ad2fb2c763071f326

Also, I would like to thank CPhill for being such an amazing person. You helped me out so much today with my math problems. Thank you!

Supergirl
May 19, 2017

#1
**+1 **

There are several answers possible ......

Using the form y = A sin ( Bx + C) + D

The period of the graph is 15 units in length.....then each quarter point = 15/4 units

The amplitude of the graph = A = 4

The midline of the graph is y = 1 = D

We can solve for B thusly

pi/2 = (15/4)B

pi/ 2 * (4/15) = B

(2/15)pi = B

And we can find C thusly......note that we are shifting the normal cosine curve to the right

1 = sin [ (2/15)pi (15/4) - C] + 1 subtract 1 from both sides

0 = sin [ ( pi/2) - C ] → cC = pi /2

So....our function is

y = 4 sin [ (2/15)pi* x - pi/2 ] + 1

Here's the graph : https://www.desmos.com/calculator/gdqmefwhyc

CPhill
May 19, 2017