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If you roll a 6-sided die 4 times, what is the probability of one roll being a multiple of 3?
A)2/3
B)16/81  
C)145/1296 
D)65/81 
E)625/1296

 Aug 13, 2020
 #1
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See the answer under your first post.

 Aug 13, 2020
 #2
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There is a 2/3 chance each time that the roll will NOT be a multiple of 3, so (2/3)^4 is the probability that none of them will be a multiple of 3.

If we subtract this from 1, we will get the probablility that at least one of the rolls is a multiple of 3. This is equal to 65/81, option D.

 

I hope this helps you, best of luck!

 Aug 13, 2020
 #3
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This is exactly the reverse of your first question about the Pirates! Out of 6^4 =1,296 permutations, there are 1040 of them whose product is a multiple of 3. Or, 1040 / 6^4 =65 /81

 Aug 13, 2020
 #4
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Another great way to solve it!

It's always reassuring when two people get the same answer. :)

Clear  Aug 13, 2020

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