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avatar+351 

If you saw the first one (a LONG time ago), then you should know the pattern:

                   i=1

                   i2=1

                   i3=i

                   i4=1

 

Now, try to solve this:

          i2016+i2015+i2014...+i2+i

 

This is actually much easier than it looks.

          36i

 

This is requires you to use the technique:

          i20162015

 

A little non-imaginary question:

In factoring, can't you just use 2-1 for everything?

Example: Factor x+1   SOLUTION: (x+1)(2-1)? LOL I don't think so (don't get me wrong: I know very well that you cannot use 1 in factoring)

 

GOOD LUCK AND MAY THE MATHS BE EVER IN YOUR FAVOR laugh

 Aug 2, 2016
 #1
avatar+351 
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indecision The title was supposed to be Imaginary Numbers 2...

 Aug 2, 2016
 #2
avatar
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i^2016 + i^2015 + i^2014........i^2 + i =0

 Aug 2, 2016

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