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Let x be a positive integer such that \(9x\equiv 1\pmod{25}\). What is the remainder when 11+x is divided by 25?

 Apr 24, 2019
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We have to find a multiple of 9, that when divided by 25 leaves a remainder of 1.

 

Therefore, 126 is congruent to 1(mod25)...so x = 126 / 9 = 14.

 

Thus, 14+11=25 and dividing this result by 25 leaves a remainder of 0.

 

-tertre

 Apr 24, 2019

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