Compute i+i^2+i^3.............i^258+i^259
Because (i,i2,i3,i4)=(i,−1,−i,1), we have i+i2+i3⋯+i258+i259=64(i−1−i+1)+i257+i258+i259. So, the desired sum is i257+i258+i259=i−1−i=−1.