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How do you solve 4^x = 12 or 1.5^-x = 0.01

 Mar 30, 2022
 #1
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Hey, you are not allowed to do 2 questions a post. We don't do your homework for you, have you tried solving these your own?

 Mar 30, 2022
 #2
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(1.) Take the logarithm of both sides of the equation to remove the variable from the exponent.

Exact Form:

x=ln(12) / ln(4)

Decimal Form:

x=1.79248125…

 

(2.)

Take the logarithm of both sides of the equation to remove the variable from the exponent.

Exact Form:

x=−ln(0.01) /ln(1.5)

Decimal Form:

x=11.35774717

 Mar 30, 2022
edited by Elijah  Mar 30, 2022

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