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What is the domain of the function \(f(x) = \sqrt{6x-3}\) ?

Enter your answer in interval notation (see the formatting tips). Rational endpoints that are not integers should be entered as fractions in simplest form.

 

 Hellp me, dont give me all of the answer, just give me a nudge.

 Jun 22, 2019
edited by CuteDramione  Jun 22, 2019
 #1
avatar+7725 
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You are spamming.

 Jun 22, 2019
 #2
avatar+75 
-3

.... ill tone it down a bit.

CuteDramione  Jun 22, 2019
 #3
avatar+7725 
0

It's because you posted the same problem twice.

MaxWong  Jun 22, 2019
 #4
avatar+75 
-5

Oh I did?

CuteDramione  Jun 22, 2019
 #5
avatar+75 
-5

no this is find the domain and the other is the range.... right? or is it left? or not right?

CuteDramione  Jun 22, 2019
 #6
avatar+7725 
0

\(\sqrt{\text{(Negative number)}}\text{ is not possible. Think about what makes }6x-3\text{ a negative number.}\)

.
 Jun 22, 2019
 #7
avatar+75 
-4

when 6x is smallar than 3

CuteDramione  Jun 22, 2019
 #8
avatar+7725 
0

Yes. Solve the inequality 6x < 3, and you get the range of values that are NOT possible to be x. 

You can find what's possible to be x afterwards, as what's NOT impossible to be x, is what's possible to be x.

MaxWong  Jun 22, 2019

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