+103 im really sorry for asking so many question and you dont need to answer them but if any one can help me with question it will be very appriciated : "a dealer paid for 2 different items 90$ (not the real given money). he sold the items and he earned 40% more on the whole deal ( he earned more then spent). on the first product he earned 5% and on the second one he earned 50%. how much did he paid for each product".
+33657 Let the price he paid for the first item be f, and the price he paid for the second item be s.
We are told that: f + s = 90 ...(1)
What he got for the first item is: 1.05*f and on the second he got 1.5*s. The sum of these two equals what he got in total, which we are told is 1.4*90, so: 1.05*f + 1.5*s = 1.4*90 ...(2)
Rearrange eqn (1) to get: f = 90 - s. Put this in eqn (2) to get 1.05*(90 - s) + 1.5*s = 1.4*90 or
1.05*90-1.05*s+1.5*s = 1.4*90
See if you can take it from here. Having found s, you can substitute this back into eqn (1) to find f.
+33657 Let the price he paid for the first item be f, and the price he paid for the second item be s.
We are told that: f + s = 90 ...(1)
What he got for the first item is: 1.05*f and on the second he got 1.5*s. The sum of these two equals what he got in total, which we are told is 1.4*90, so: 1.05*f + 1.5*s = 1.4*90 ...(2)
Rearrange eqn (1) to get: f = 90 - s. Put this in eqn (2) to get 1.05*(90 - s) + 1.5*s = 1.4*90 or
1.05*90-1.05*s+1.5*s = 1.4*90
See if you can take it from here. Having found s, you can substitute this back into eqn (1) to find f.
