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hi there!!

here's the problem ive been working for like an hour on and still cant get right: 

Calculate

\(\arccos \sqrt{\cfrac{1+\sqrt{\cfrac{1+\sqrt{\cfrac{1-\sqrt{\cfrac{1+\cfrac{\sqrt{3}}{2}}{2}}}{2}}}{2}}}{2}}.\)

As usual, the output of an inverse trig function should be in radians.

 

ive attempted this problem so many times but got a different wrong answer every time i approached it so it would be great if someone could just walk me through it. (please dont just give me an answer i really need to understand this for my class..)

 

thank you sm in advance!!

 Sep 4, 2023
 #1
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The answer is 13*pi/96.  The solution has been posted here:

 

https://web2.0calc.com/questions/pre-calc-problem

 Sep 5, 2023
 #2
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that solution is incorrect...

 Sep 5, 2023
 #4
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Hi   heartSTORM907,

 

Alan's answer isn't wrong.

Even if there is some small error the working is very detailed and solid.

Which bit don't you understand?

 

I have opened the earlier question so you can answer there is you want to.

 

Make sure you also post a link on this thread if you continue this elsewhere.

Melody  Sep 5, 2023
 #3
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1 - Start at the top: sqrt((sqrt(3) / 2 + 1)/2)=0.9659258262890682867497431997289
2 - [1 - 0.9659258262890682867497431997289]
3 - sqrt[0.0340741737109317132502568002711 / 2]
4 -sqrt [0.13052619222005159154840622789549+1]/2
5 - sqrt[0.56526309611002579577420311394775]
6 - [(0.75183980747897739640751940637696)+1] / 2
7 - sqrt[0.87591990373948869820375970318848]
8 - 0.93590592675732570029170724946674
9 - Arccos[0.93590592675732570029170724946674]


10 - [11 Pi] / 96  [in radians]
Note: This question is slightly different from the above link, which gives: [13 Pi] / 96.

 Sep 5, 2023
 #5
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thank you so so so so much!!!!! i think i understand now :)

heartSTORM907  Sep 6, 2023

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