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Why does raised to an exponent change when using even numbers? You'd expect that a negative number with an even exponent to always come out positive. Can someone explain the pattern:

i^2= -1, i^4+ 1, i^6= 1, i^8= -1, i^10= 1, and so on. Why does it bounce from negative to positve? 

Guest Nov 18, 2014

Best Answer 

 #1
avatar+91510 
+10

By definition

$$i=\sqrt{-1}$$

Remember this is not a real number it is an imaginary number!

squares and square roots cancle each other out so

 

$$\\i^2=(\sqrt{-1})^2 = -1\\\\
i^4=i^2\times i^2=-1\times-1=+1\\\\
i^6=i^4\times i^2=1\times-1=-1\\\\
i^8=i^6\times i^2=-1\times-1=+1\\\\
i^{10}=i^8\times i^2=+1\times-1=-1\\\\$$

 

does that help you to understand?  

Melody  Nov 19, 2014
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1+0 Answers

 #1
avatar+91510 
+10
Best Answer

By definition

$$i=\sqrt{-1}$$

Remember this is not a real number it is an imaginary number!

squares and square roots cancle each other out so

 

$$\\i^2=(\sqrt{-1})^2 = -1\\\\
i^4=i^2\times i^2=-1\times-1=+1\\\\
i^6=i^4\times i^2=1\times-1=-1\\\\
i^8=i^6\times i^2=-1\times-1=+1\\\\
i^{10}=i^8\times i^2=+1\times-1=-1\\\\$$

 

does that help you to understand?  

Melody  Nov 19, 2014

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