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In a boarding kennle, dogs number 12 more than 2 times the number of cats. If there are 75 animals, how many cats are boarded?

Guest Jun 17, 2015

Best Answer 

 #1
avatar+26329 
+10

Let d stand for number of dogs and c stand for number of cats.

 

d = 2*c + 12                ...(1)

d + c = 75                   ...(2)

 

Replace d in (2) using (1)

2*c + 12 + c = 75

 

3*c + 12 = 75

 

3*c = 75 - 12

3*c = 63

 

c = 63/3

 

c = 21

 

So there are 21 cats  (and 2*21 + 12 = 54 dogs)

.

Alan  Jun 17, 2015
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1+0 Answers

 #1
avatar+26329 
+10
Best Answer

Let d stand for number of dogs and c stand for number of cats.

 

d = 2*c + 12                ...(1)

d + c = 75                   ...(2)

 

Replace d in (2) using (1)

2*c + 12 + c = 75

 

3*c + 12 = 75

 

3*c = 75 - 12

3*c = 63

 

c = 63/3

 

c = 21

 

So there are 21 cats  (and 2*21 + 12 = 54 dogs)

.

Alan  Jun 17, 2015

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