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In an elevator in a tall building is at a point 180 feet above the ground .The elevator moves at a rate of 12 feet per secound.

1 Represent how far above the ground the elevator is, y,after descening for x seconds

 

2 Using your equation from (part a),how long will it take the elevator to reach the ground level?

 

3 The elevator starts on the ground level,and then ascends 250 feet ,to the top floor.How long does it take the elevator to reach the top floor?(Hint: You will not use the excat same equation you did for (part a )or (part b).

 Apr 30, 2015

Best Answer 

 #1
avatar+129899 
+5

1. y = 180 - 12x

 

2.  At ground level, y will = 0   ....so

0  =  180 - 12x    add 12x to both sides

12x  = 180             divide both sides by 12

x  = 15  seconds

 

3.  We have

250  = 12x     divide both sides by 12

250 / 12 = x   =  about 20.83 seconds

 

  

 Apr 30, 2015
 #1
avatar+129899 
+5
Best Answer

1. y = 180 - 12x

 

2.  At ground level, y will = 0   ....so

0  =  180 - 12x    add 12x to both sides

12x  = 180             divide both sides by 12

x  = 15  seconds

 

3.  We have

250  = 12x     divide both sides by 12

250 / 12 = x   =  about 20.83 seconds

 

  

CPhill Apr 30, 2015

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