In cyclic quadrilateral PQRS,
Find the largest angle in quadrilateral PQRS, in degrees.
Let P=3x,Q=4x,R=5x. Then, the sum of the angles in quadrilateral PQRS is [3x + 4x + 5x + 6x = 180^\circ,]so x=30∘. The largest angle is ∠R=5⋅30∘=150∘.
im not sure if the math there adds up because then (3x+4x+5x+6x) = 180 would make x equal to 10