+122 In how many ways can a resident of Enigma use only bills to purchase a gyroscope that costs 97 confusions?
help!!!!!!!!! tysmmm
+122 On planet Enigma, the residents use a currency called the confusion. There are only 2 confusion bills on Enigma, one worth 8 confusions and the other worth 11 confusions. There are also some coins of smaller value, but each weighs over 10 kilograms, so they are difficult to carry around. In how many ways can a resident of Enigma use only bills to purchase a toaster that costs 96 confusions? (Everybody knows, of course, that vendors on Enigma do not give change, so residents must make their purchases with exact change.) Solution: Since we have two types of bills, we have the Diophantine equation $8a + 11b = 96$, where $a$ and $b$ are non-negative integers. By inspection, we find the solution $a = 12$ and $b = 0$. Note that once we have found a particular solution $(a,b)$, we can decrease $a$ by 11 and increase $b$ by 8 to obtain another solution, because the overall increase in $8a + 11b$ is $8 \cdot (-11) + 11 \cdot 8 = -88 + 88 = 0$. We can also increase $a$ by 11 and decrease $b$ by 8. Furthermore, every solution to the equation $8a + 11b = 96$ can be obtained from the solution $(a,b) = (12,0)$ in this way. So, decreasing $a$ by 11 and increasing $b$ by 8 repeatedly, we get the solutions $(1,8)$, $(-10, 16)$, $(-21, 24)$, and so on. Increasing $a$ by 11 and decreasing $b$ by 8 repeatedly, we get the solutions $(23,-8)$, $(34,-16)$, $(45,-24)$, and so on. However, since $a$ and $b$ are nonnegative, the only solutions are $(12,0)$ and $(1,8)$. There are 2 solutions.
^^first problem (part a) solution
There is only one way you can buy a gyroscope that costs 97 confusions:
8 x 8 confusions + 3 x 11 confusions = 97 confusions.
+122 there is also a part c... if someone would like to try these tysmmmmmm
In how many ways can a resident of Enigma use only bills to purchase a single math book page that costs 69 confusions?
