+489 In how many ways can seven beads of distinct colors be put on the hexagonal grid shown, if reflections and rotations of an arrangement are considered equivalent?
+118687 I am not sure but this is what i am thinking
Any on of the 7 can go in the middle
Place one more is a specific spot - Say the red one
There are 5 more places to fill so that is 5!
Now if the middle one and one side one is fixed then there is only one axis of symmetry that counts, I mean the one that goes through the centre one and the red one.
So maybe the answer is
\(\frac{7*5!}{2}=7*3*4*5=420\)
I am ot sure though.
+118687 Asked again here
https://web2.0calc.com/questions/help-with-this-question-https-web2-0calc-com-questions
But please answer on the original post, that is the one of have attempted the answer on.
