In right triangle $ABC$, we have $AB = 10$, $BC = 24$, and $\angle ABC = 90^\circ$. If $M$ is on $\overline{AC}$ such that $\overline{BM}$ i

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In right triangle ABC, we have AB = 10, BC = 24, and $\angle ABC = 90^\circ$.

If M is on $\overline{AC}$ such that $\overline{BM}$ is an angle bisector of $\triangle ABC$, then what is $\cos \angle ABM$ ?

michaelcai Nov 18, 2017

edited by Melody Nov 19, 2017

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Best Answer

angle ABC is a right angle

and BM bisects ABC then angle ABM is 45 degrees and cos 45 degrees = 1/sqrt2

Melody Nov 19, 2017

Melody · Answer 1 · 2017-11-19T06:01:31

angle ABC is a right angle

and BM bisects ABC then angle ABM is 45 degrees and cos 45 degrees = 1/sqrt2