+0  
 
+2
680
1
avatar+598 

In right triangle ABC, we have AB = 10, BC = 24, and \(\angle ABC = 90^\circ\).

 

If M is on \(\overline{AC}\) such that \(\overline{BM}\) is an angle bisector of \(\triangle ABC\), then what is \(\cos \angle ABM\) ?

michaelcai  Nov 18, 2017
edited by Melody  Nov 19, 2017

Best Answer 

 #1
avatar+93362 
+2

angle ABC is a right angle

and  BM bisects ABC then angle ABM is 45 degrees and cos 45 degrees =   1/sqrt2

Melody  Nov 19, 2017
 #1
avatar+93362 
+2
Best Answer

angle ABC is a right angle

and  BM bisects ABC then angle ABM is 45 degrees and cos 45 degrees =   1/sqrt2

Melody  Nov 19, 2017

5 Online Users

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.