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In right triangle ABC, we have AB = 10, BC = 24, and \(\angle ABC = 90^\circ\).

 

If M is on \(\overline{AC}\) such that \(\overline{BM}\) is an angle bisector of \(\triangle ABC\), then what is \(\cos \angle ABM\) ?

 Nov 18, 2017
edited by Melody  Nov 19, 2017

Best Answer 

 #1
avatar+118587 
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angle ABC is a right angle

and  BM bisects ABC then angle ABM is 45 degrees and cos 45 degrees =   1/sqrt2

 Nov 19, 2017
 #1
avatar+118587 
-1
Best Answer

angle ABC is a right angle

and  BM bisects ABC then angle ABM is 45 degrees and cos 45 degrees =   1/sqrt2

Melody Nov 19, 2017

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