In right triangle $ABC$ , we have $AB = 10$ , $BC = 24$ , and $\angle ABC = 90^\circ$ . If $M$ is on $\overline{AC}$ such that $\overline{BM}$ i

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In right triangle ABC, we have AB = 10, BC = 24, and $\angle ABC = 90^\circ$ .

If M is on $\overline{AC}$ such that $\overline{BM}$ is an angle bisector of $\triangle ABC$ , then what is $\cos \angle ABM$ ?

michaelcai Nov 18, 2017

edited by Melody Nov 19, 2017

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Best Answer

angle ABC is a right angle

and BM bisects ABC then angle ABM is 45 degrees and cos 45 degrees = 1/sqrt2

Melody Nov 19, 2017

Melody · Answer 1 · 2017-11-19T06:01:31

angle ABC is a right angle

and BM bisects ABC then angle ABM is 45 degrees and cos 45 degrees = 1/sqrt2

In right triangle ABCABC, we have AB=10AB = 10, BC=24BC = 24, and ∠ABC=90∘\angle ABC = 90^\circ. If MM is on ¯AC\overline{AC} such that ¯BM\overline{BM} i