In right triangle $ABC$, we have $\angle BAC = 90^\circ$ and $D$ is on $\overline{AC}$ such that $\overline{BD}$ bisects $\angle ABC$. If $AB = 12$ and $BC = 15$, then what is $\cos \angle BDC$?

michaelcai
Nov 14, 2017

#1**+1 **

If anyone does find this answer, let me also know the sin and tangent of the angle. Thanks!

TheMathCoder
Apr 25, 2018