In the above graph you see the functions f(x) = (x+3)(x-3) , g(x) = 0,5x^2 ~~and h(x) = x-3~~

d. Calculate the x coordinates of the points of intersection of the graphs of f and g .

e. Theres the function notation j(x) = (x+ 2 1/2)^2 - 5 . Give by logically reasoning the coordinates of the top of the graph of function j

Guest Apr 3, 2019

#1**+1 **

g(x) = 0.5x^2

is NOT one of those graphs!

The curve labled g is not that function.

Melody Apr 3, 2019

#2**+1 **

In the above graph you see the functions f(x) = (x+3)(x-3) , g(x) = 0,5x^2 and h(x) = x-3

Omi67 Apr 3, 2019

#3**+1 **

OK.... we've discovered the graph of .5 x^2 is not there..... The question asks to CALCULATE the points of intersection...set the two GIVEN equations equal to each other and calculate the values of x where the graphs are equal....use these value(s) of x to substitute into either of the equations to calculate the corresponding y values.

(x+3)(x-3) = 0.5 x^2 solve for x's

x^2 -9 = 0.5 x^2 continue to solve for x then sub into one of the original equations to find the corresponding y's.......

ElectricPavlov Apr 3, 2019

#6**0 **

Okay so....

(x+3)(x-3) = 0.5x^2 + x + 3

x^2 -9 = 0.5x^2 + x + 3

10x^2 -90 = 5x^2 + 10x + 30

5x^2 + 10x + 30 = 10x^2 -90

5x^2 + 10x + 120 = 10x^2

5x^2 + 10x + 120 = 10x^2

-5x^2 + 10x + 120 = 0

What would you do now then? I'm kinda stuck oof

Guest Apr 7, 2019

edited by
Guest
Apr 7, 2019

edited by Guest Apr 7, 2019

edited by Guest Apr 7, 2019