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# In the above graph you see the functions f(x) = (x+3)(x-3) and g(x) = 0,5x^2

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6 In the above graph you see the functions f(x) = (x+3)(x-3) , g(x) = 0,5x^2 and h(x) = x-3

d. Calculate the x coordinates of the points of intersection of the graphs of f and g .

e. Theres the function notation j(x) = (x+ 2 1/2)^2 - 5 . Give by logically reasoning the coordinates of the top of the graph of function j

Apr 3, 2019

#1
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g(x) = 0.5x^2

is NOT one of those graphs!

The curve labled g is not that function.

Apr 3, 2019
#2
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In the above graph you see the functions f(x) = (x+3)(x-3) , g(x) = 0,5x^2 and h(x) = x-3  Apr 3, 2019
#3
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OK.... we've discovered   the graph of .5 x^2 is not there..... The question asks to CALCULATE the points of intersection...set the two GIVEN equations equal to each other and calculate the values of  x   where the graphs are equal....use these value(s) of x to substitute into either of the equations to calculate the corresponding y values.

(x+3)(x-3) = 0.5 x^2     solve for x's

x^2 -9 = 0.5 x^2           continue to solve for x   then sub into one of the original equations to find the corresponding y's.......

Apr 3, 2019
#6
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Okay so....

(x+3)(x-3) = 0.5x^2 + x + 3

x^2 -9 = 0.5x^2 + x + 3

10x^2 -90 = 5x^2 + 10x + 30

5x^2 + 10x + 30 = 10x^2 -90

5x^2 + 10x + 120 = 10x^2

5x^2 + 10x + 120 = 10x^2

-5x^2 + 10x + 120 = 0

What would you do now then? I'm kinda stuck oof

Guest Apr 7, 2019
edited by Guest  Apr 7, 2019
edited by Guest  Apr 7, 2019
#4
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Whoops OP here, I accidentally missed a part of the function when reading over the assignment. g(x) = 0,5x^2 is supposed to be g(x) = 0,5x^2 + x + 3

Apr 4, 2019
#5
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I think you are better off to post it as a new CORRECT question.

Melody  Apr 4, 2019