In the above graph you see the functions f(x) = (x+3)(x-3) , g(x) = 0,5x^2 and h(x) = x-3
d. Calculate the x coordinates of the points of intersection of the graphs of f and g .
e. Theres the function notation j(x) = (x+ 2 1/2)^2 - 5 . Give by logically reasoning the coordinates of the top of the graph of function j
+118667 g(x) = 0.5x^2
is NOT one of those graphs!
The curve labled g is not that function.
+12531 In the above graph you see the functions f(x) = (x+3)(x-3) , g(x) = 0,5x^2 and h(x) = x-3
+37146 OK.... we've discovered the graph of .5 x^2 is not there..... The question asks to CALCULATE the points of intersection...set the two GIVEN equations equal to each other and calculate the values of x where the graphs are equal....use these value(s) of x to substitute into either of the equations to calculate the corresponding y values.
(x+3)(x-3) = 0.5 x^2 solve for x's
x^2 -9 = 0.5 x^2 continue to solve for x then sub into one of the original equations to find the corresponding y's.......
Okay so....
(x+3)(x-3) = 0.5x^2 + x + 3
x^2 -9 = 0.5x^2 + x + 3
10x^2 -90 = 5x^2 + 10x + 30
5x^2 + 10x + 30 = 10x^2 -90
5x^2 + 10x + 120 = 10x^2
5x^2 + 10x + 120 = 10x^2
-5x^2 + 10x + 120 = 0
What would you do now then? I'm kinda stuck oof
