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In the card game bridge, each of 4 players is dealt a hand of 13 of the 52 cards. What is the probability that each player receives exactly one Ace? (You may use a calculator to compute the probability, but answer as an exact number. Entering a few decimal places of a nonterminating decimal is not considered exact; if you reach such an answer, enter it as a fraction.)

 Apr 15, 2015

Best Answer 

 #2
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Picture 52 locations divided into 4 groups of 13.

The first Ace can go anywhere, the second Ace has 39 of 51 possible locations in which to go, the third has 26 of a possible 50 and the fourth 13 of a possible 49.

That works out to about 10.5498%, you should be able to work out the exact fractional value.

 Apr 15, 2015
 #1
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I'd like to know too.  

 Apr 15, 2015
 #2
avatar+890 
+5
Best Answer

Picture 52 locations divided into 4 groups of 13.

The first Ace can go anywhere, the second Ace has 39 of 51 possible locations in which to go, the third has 26 of a possible 50 and the fourth 13 of a possible 49.

That works out to about 10.5498%, you should be able to work out the exact fractional value.

Bertie Apr 15, 2015
 #3
avatar+109812 
0

Thanks Bertie, that wasn't so hard after all.  Wish I had thought of it.  LOL   

 

$$\\1\times \frac{39}{51}\times \frac{26}{50}\times \frac{13}{49}=\frac{13182}{124950}=\frac{6591}{62475}$$

.
 Apr 15, 2015

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