+63 In the circle shown below, ∠BAC is a central angle, r is the length of AB, and θ is the measure of ∠BAC in degrees.
https://lh5.googleusercontent.com/vGxgQ60PGu4WCkFdHDXFR0d0rVx_7wMLJeY3zCtQt6YKA_2JQU4UnzT12axHzV3-6MrC2TykXFsOvRbBqpUZSZYkHy_c63yjSiY3ro-DxnMDMiIauumG3bGMqMCaFV-EBNQaAKs_
Which of the following would be used to derive the formula for the area of sector BAC?
The equation that sets the ratio of θ to the length of arc BC equal to the ratio of 360 to the circumference of the circle shown above.
The equation that sets the ratio of θ to the measure of arc BC equal to the ratio of the area of sector BAC to the area of the circle shown above.
The equation that sets the ratio of the length of r to the area of the circle equal to the ratio of the area of sector BAC to the area of the circle shown above.
The equation that sets the ratio of θ to the area of sector BAC equal to the ratio of 360 to the area of the circle shown above.
+128406 The equation that sets the ratio of θ to the area of sector BAC equal to the ratio of 360 to the area of the circle shown above.
To see why this is so.....let the radius = 1
So the area of the circle = pi(1)^2 = pi
Now....imagine that θ = 60°
So
60 / area of sector = 360 / pi
60 /area of sector = 360 /pi we can write
area of sector / 60 = pi /360 multiply both sides by 60
area of sector = (60 /360) pi = pi /6
Since 60° is 1/6 of 360°.....the area should be (1/6) pi = pi /6
