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In the continuation of this array of positive integers, in which column is the number 12 000?

12 9102526
438112427
567122328
161514132229
171819202130
363534333231

 

Options:

1. 99

2. 100

3. 101

4. 102

5. 103

 

Thanks in advance for the help!

 Dec 8, 2018
edited by Guest  Dec 8, 2018
 #1
avatar+98102 
+1

Here's my best attempt

 

It appears that all even squares - except 1 -  will terminate in the 1st column

 

The next perfect square after 12000 is 12100

The square root of 12100 is 110

So....we will have a square that will have 110 integers on each side

 

12100 will be in the 1st column.....

12109 will be in the second column = 12100 - 12109 + 1 = 2

12108 will be in the 3rd column = 12100 - 12108 + 1 = 3

 

So.....to find the column containing 12000 we can evaluate this

 

12100 - 12000 + 1  =

 

100 + 1  =

 

101 

 

cool cool cool

 Dec 9, 2018
 #2
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0

Thanks!

Guest Dec 9, 2018

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