In the continuation of this array of positive integers, in which column is the number 12 000?

Here's my best attempt

It appears that all even squares - except 1 -  will terminate in the 1st column

The next perfect square after 12000 is 12100

The square root of 12100 is 110

So....we will have a square that will have 110 integers on each side

12100 will be in the 1st column.....

12109 will be in the second column = 12100 - 12109 + 1 = 2

12108 will be in the 3rd column = 12100 - 12108 + 1 = 3

So.....to find the column containing 12000 we can evaluate this

12100 - 12000 + 1  =

100 + 1  =

101