In the diagram, K, O and M are the centers of the three semi-circles. OC = 32 and CB = 36,

What is the area of the semi-circle with center k?

qwertyzz Aug 6, 2020

#1**0 **

Ok let's do this

the diameter of circle M is [** 36**] so the radius is 18, the area of semicircle M is 18^2*pi which is 324pi then /2 which is 162pi

Now let's move on, the radius of circle O=32+36 which is 68, that will equal to (68^2)/2 which is 2312 and the diameter is [** 136**]

Now with these two Diameters, we can find the area of circle K, first we find the radius, that will be (136-36)/2 which is 50, then 50^2/2 which is 1250, finally multiply by pi and we get

1250pi

Guest Aug 6, 2020