We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website.
Please click on "Accept cookies" if you agree to the setting of cookies. Cookies that do not require consent remain unaffected by this, see
cookie policy and privacy policy.
DECLINE COOKIES

In the equation above, a, b, and c are constans. If the equation has infinitely many solutions, which of the following must be equal to c?

2(x+b) = ax+c

A) a

B) b

C) 2a

D) 2b

I know the answer is D but can anyone explain it? Thanks!!!!!!!!!!

AND THIS ONE!

If 3x-6y = 9z, which of the following expressions is equivalent to x^2 - 4xy + 4y^2

A) 9z

B) 3z^2

C) 9z^2

I honestly suck at theses problems with mutiple constants invovled in an equation. Does anybody have tips solving these types of problems? It will make my day. Thank YOU!!!!

mrlevan3 Aug 8, 2018

edited by
Guest
Aug 8, 2018

#1**+1 **

2(x+b) = ax+c Simplify

2x + 2b = ax + c If this has infinite solutions, then a = 2 and 2b = c

So...note that

2x + 2b = 2x + c will be true for any real x whenever 2b = c

If 3x-6y = 9z, which of the following expressions is equivalent to x^2 - 4xy + 4y^2

Dividing the first equation through by 3, we have

x - 2y = 3z (1)

Notice that x^2 - 4xy + 4y^2 factors as (x -2y) ( x - 2y) (2)

So subbing (1) into (2) we get (3z) (3z) = 9z^2

CPhill Aug 8, 2018