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In the equation (w^3 + x^3 + y^3 = z^3) , w^3, x^3, y^3, and z^3 are distinct consecutive positive perfect cubes listed in ascending order. What is the smallest possible value of z?

Guest Oct 29, 2018

Best Answer 

 #1
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The smallest possible value of  z=6, so that:

w^3+x^3+y^3 =z^3

3^3 + 4^3 + 5^3 = 6^3

27 + 64 + 125 = 216

Guest Oct 29, 2018
 #1
avatar
+1
Best Answer

The smallest possible value of  z=6, so that:

w^3+x^3+y^3 =z^3

3^3 + 4^3 + 5^3 = 6^3

27 + 64 + 125 = 216

Guest Oct 29, 2018

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