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In the figure, if MR = MK, the measure of arc MK is 130 degrees, and measure of arc MQ is 23 degrees, then what is angle RPK, in degrees?

 

 Oct 31, 2020
 #1
avatar+452 
+1

arc RK = 360 - 260 = 100º

 

∠RMK = 100 / 2 = 50º

 

∠MKQ = 23 / 2 = 11.5º

 

∠KPM = 180 - (50 + 11.5) = 118.5º

 

∠RPK = 1/2 (360 - 118.5 * 2) = 61.5º

 Oct 31, 2020
 #2
avatar+111602 
+1

In the figure, if MR = MK, the measure of arc MK is 130 degrees, and measure of arc MQ is 23 degrees, then what is angle RPK, in degrees?

 

Let X be the centre

 

Mz understanding of the question is that   

 

and you want 

 

When two angles stand on the same arc, the angle at the centre is twice the angle on the circumference,

so

 

 

None of the other info is relevant.

 

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For some reason this is not displaying properly, so hee is a picture of it

 Oct 31, 2020
edited by Melody  Oct 31, 2020
edited by Melody  Oct 31, 2020
 #3
avatar+111602 
0

Test post

Still not displaying properly   sad

 Nov 8, 2020
edited by Melody  Nov 8, 2020

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