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In the figure, triangles \(ABC\) and \(BCD\) are equilateral triangles.What is the value of \(AD/ BC\) when expressed in simplest radical form?- 

 Aug 5, 2020
edited by Guest  Aug 5, 2020
 #1
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If they are equilateral triangles, all of the lines in the figure are of the same length

   then  AB/BC = 1

 Aug 5, 2020
 #2
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Sorry, I just changed it. The question was supposed to ask what AD/BC was, not AB/BC.  

Guest Aug 5, 2020
 #3
avatar+26626 
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Alright, Knucklehead  cheeky

 

the diagonal is 2 * height of the equilateral triangles       using side length = L

  height :

      sin 60 = height/L

        L sin 60 = height                   sin 60    is   sqrt 3/2

 

            2 * height then equals   L sqrt 3   = AD 

 

 

then   AD      to      BC  which equals L   becomes      Lsqrt3  / L    = sqrt 3

ElectricPavlov  Aug 5, 2020
edited by ElectricPavlov  Aug 5, 2020

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