+13 In the figure, triangles \(ABC\) and \(BCD\) are equilateral triangles.What is the value of \(AD/ BC\) when expressed in simplest radical form?- 
+37159 If they are equilateral triangles, all of the lines in the figure are of the same length
then AB/BC = 1
Sorry, I just changed it. The question was supposed to ask what AD/BC was, not AB/BC.
+37159 Alright, Knucklehead 
the diagonal is 2 * height of the equilateral triangles using side length = L
height :
sin 60 = height/L
L sin 60 = height sin 60 is sqrt 3/2
2 * height then equals L sqrt 3 = AD
then AD to BC which equals L becomes Lsqrt3 / L = sqrt 3
