In the figure, triangles \(ABC\) and \(BCD\) are equilateral triangles.What is the value of \(AD/ BC\) when expressed in simplest radical form?-

IntGeosc1 Aug 5, 2020

edited by
Guest
Aug 5, 2020

#1**+1 **

If they are equilateral triangles, all of the lines in the figure are of the same length

then AB/BC = 1

ElectricPavlov Aug 5, 2020

#2**0 **

Sorry, I just changed it. The question was supposed to ask what AD/BC was, not AB/BC.

Guest Aug 5, 2020

#3**+1 **

Alright, Knucklehead

the diagonal is 2 * height of the equilateral triangles using side length = L

height :

sin 60 = height/L

L sin 60 = height sin 60 is sqrt 3/2

2 * height then equals L sqrt 3 = AD

then AD to BC which equals L becomes Lsqrt3 / L = sqrt 3

ElectricPavlov
Aug 5, 2020