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In the game 'Cover It Up' two standard six-faced dice are rolled and their sum determined. The player can then cover that number on the game board or any two numbers that have that sum. For example, if you roll a 3 and 5, you can cover the 8, the 1 and 7, the 2 and 6, or the 3 and 5. What is the probability of being able to cover the 9 on the first roll of the two dice? Express your answer as a common fraction.

 Feb 27, 2021
 #1
avatar+48 
0

So the number of ways we can get a number greater then 9, if we roll a 1: 0, 2:0, 3:0, 4:1, 5:2, 6:3 so in total there are 6 ways to cover 9 on the first roll. 36 possible rolls in total divided by 2 for over counting  so 1/3 I would think...

 Feb 27, 2021
 #2
avatar+48 
0

No 1/6

Pendragon107  Feb 27, 2021
 #3
avatar+30781 
+1

36 possible rolls

What will cover a '9'

5 4

4 5

3 6

6 3       4 rolls

 

The you can roll greater than 9

10:

6 4

4 6

5 5       3 rolls

 

11:

 

5 6   2 rolls

6 5

 

12 :

6 6    1 roll             10 ways out of 36 rolls           5/18

 Feb 27, 2021

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