In triangle PQR, M is the midpoint of PQ Let X be the point on QR such that PX bisects

Let's first find the length of PX. Since PX bisects angle QPR, we have:

PQ / PX = PR / QR

 

We can simplify this using the lengths of PQ and PR that we know:

36 / PX = 22 / QR

 

Solving for PX:

PX = (36 * QR) / 22

 

Since M is the midpoint of PQ, we have:

PQ = 2 * MY = 2 * 8 = 16

 

So QR can be found as:

QR = PR + PQ = 22 + 16 = 38

 

Substituting into our expression for PX:

PX = (36 * 38) / 22 = 54

 

Next, let's find the length of PY. Since MY = 8, we can use the Pythagorean Theorem to find PY:

PY^2 + MY^2 = PX^2 PY^2 + 8^2 = 54^2 PY^2 = 54^2 - 8^2 = 2916 PY = sqrt(2916) = 54

 

Finally, we can use the formula for the area of a triangle:

Area = (1/2) * PY * PX Area = (1/2) * 54 * 54 Area = 1458

 

Therefore, the area of triangle PYR is 1458.