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The lengths of two sides of a triangle are 33 units and 42 units. The third side also has an integral length. What is the least possible number of units in the perimeter of the triangle?

 May 29, 2018
 #1
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42 -33 + 1 = 10 units - the 3rd side.

10 + 33 + 42 = 85 units - the perimeter of the triangle.

 May 29, 2018
 #2
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Confusedperson  Jun 2, 2018
 #3
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In a triangle the difference of any 2 sides must be greater than the lenght of the third side. 

Otherwise the 3 sides will not be able to join together!

Try drawing triangles on a peice of paper and try to be comfortable that this is the truth.

 

So 

42-33= 9

the third side must be more than 9.

Since it has an integer length, it's smallest vaue must be 10.

 

The perimeter is the sum of all the sides

42+33+9  is going to be the smallest possible perimeter.

 Jun 3, 2018

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